While I was doing quickie problems, I saw someone was asked to show a sample of the Fibonacci Sequence. This one only took about 3 minutes. Simple math.
You can sum up the problem as a+b=c, b+c=d, c+d=e, etc for infinity. For mine, I stopped at 2 million whatever.
var x=0; y=1;
while (x<1000000) {
var z = x+y;
x = y; y = z;
document.write(z + "<br>");
}
Like I said. Simple math. You can look at my CodePen and adjust the while loop to make it go higher, if you like.
I came across a FizzBuzz problem while trying to come up with some sample code. The problem is pretty simple.
Write a program that prints the numbers from 1 to 100. But for multiples of 3 print “Fizz” instead of the number and for the multiples of five print “Buzz”. For numbers which are multiple of both 3 and 5, print “FizzBuzz”.
Multiple sources said that only 1% of programmers could solve this problem. That makes me think too many people call themselves programmers.
It took me about 10 minutes to come up with this in javascript:
for (var i=1; i <=100; i++) {
var x = '';
if (!(i%3)) {
x += 'Fizz';
}
if (!(i%5)) {
x += 'Buzz';
}
if (x.length == 0) {
x = i;
}
document.write(x + "<br>");
}
That worked great. You can see it at CodePen. After I finished, I looked at some other answers and found a couple of ways to improve it. Initially, I wanted to else if all the way through my options, but I had a brainfart and didn’t think of checking if it is divisible by 15. You can also check to see if x is null and if it is, write i, but I didn’t want to do it that way. Here is the final code (CodePen):
for (var i=1; i <=100; i++) {
var x = '';
if (!(i%15)) {
x = 'FizzBuzz';
} else if (!(i%3)) {
x = 'Fizz';
} else if (!(i%5)) {
x = 'Buzz';
} else {
x = i;
}
document.write(x + "<br>");
}
I hope you enjoyed that. It was a fun exercise. I’ll probably write one in ColdFusion soon.